How Do Callable Fields Work with Multimethods?

Consider:

class Foo
    var bar = fn(i) print("field")
    def bar(i) print("method")
end

var foo = Foo new()
foo bar(123)

The last line can be interpreted two ways:

1. Look up bar, then invoke the result.
2. Call the bar() method, passing in 123.

Both are valid use cases, how can they be distinguished? In the current system, it would always be given the second interpretation. If the class is like:

class Foo
    var bar = fn(i) print("field")
end

When you try to do:

Foo new() bar(123)

It will simply fail to find a method, since it's looking for one specialized to (this Foo, i Int) and all that exists is the field getter: (this Foo). What to do?

Option 1: No Callables

The Smalltalk/Io/Ruby solution is to not have functions. An expression like foo bar(123) always means "call the method bar passing in 123" because there are no directly invocable objects. If bar was a field holding a callable, you'd have to do:

foo bar call(123)

This solves the problem, but it's kind of ugly. Multimethods are a step towards being more functional, so it seems weird for the syntax to step back.

Option 2: Fallback Dispatch

Maybe we could just try both interpretations in order. So if you do:

foo bar(123)

First it will try to find a method specialized to (this Foo, arg Int). If it finds that, good. If not, it then tries to find (this Foo). If that succeeds, it then tries to immediately invoke the result passing in 123.

That would work, I think, but it feels ugly.